# Line slope calculator x+5y=17

**Straight line given by points A[2; 3] and B[7; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+3.4

**Canonical form of the line equation:**x+5y-17 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -t+3 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 17

**Y intercept:**y

_{0}= q = 3.4

**Distance line from the origin:**d

_{0}= 3.334

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**5x-y-20 = 0

**Vector OA = (2; 3) ; |OA| = 3.6056**

**Vector OB = (7; 2) ; |OB| = 7.2801**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 40°21'52″ = 0.7045 rad**