# Line slope calculator 3x+5y=31

**Straight line given by points A[2; 5] and B[7; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+6.2

**Canonical form of the line equation:**3x+5y-31 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -3t+5 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 10.3333

**Y intercept:**y

_{0}= q = 6.2

**Distance line from the origin:**d

_{0}= 5.3165

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[4.5; 3.5]

**Perpendicular Bisector equation:**5x-3y-12 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (7; 2) ; |OB| = 7.2801**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 52°15'11″ = 0.912 rad**