# Class 8 NCERT Solutions – Chapter 2 Linear Equations in One Variable – Exercise 2.1

**Question 1. Solve for x: x – 2 = 7**

**Solution:**

x – 2 = 7

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free classeswhich will definitely help them in making a wise career choice in the future.x=7+2 (Adding two on both sides of equation)

x=9

**Question 2. Solve for y: y + 3 = 10**

**Solution:**

y + 3 = 10

y = 10 –3 (Subtracting 3 from both sides of equation)

y = 7

**Question 3. Solve for z: 6 = z + 2**

**Solution:**

6 = z + 2

z + 2 = 6 (Rearranging to standard form)

z = 6 – 2 (Subtracting two from both sides)

z = 4

**Question 4. Solve for x: 3/7 + x = 17/7**

**Solution:**

3/7 + x = 17/7

x = 17/7 – 3/7 (Subtracting 3/7 on both sides)

x = 14/7 (Simplifying the equation)

x = 2

**Question 5. Solve for x: 6x = 12**

**Solution:**

6x = 12

x = 12/6 (Dividing both sides by 6)

x = 2

**Question 6. Solve for t: t/5 = 10**

**Solution:**

t/5 = 10

t = 10 × 5 (multiplying both sides by 5)

t = 50

**Question 7. Solve for x: 2x/3 = 18**

**Solution:**

2x/3 = 18

2x = 18 × 3 (Multiplying both sides by 3)

2x = 54

x = 54/2 (Dividing both sides by 2)

x = 27

**Question 8. Solve for y: 1.6 = y/1.5**

**Solution:**

1.6 = y/1.5

y/1.5 = 1.6 (Rearranging to standard form)

y = 1.6 × 1.5 (Multiplying both sides by 1.5)

y = 2.4

**Question 9. Solve for x: 7x – 9 = 16**

**Solution:**

Given that 7x – 9 = 16

7x = 16+9 (Adding 9 on both sides of equation)

7x = 25

x = 25/7 (Dividing both sides by 7)

**Question 10. Solve for y: 14y – 8 = 13**

**Solution:**

14y – 8 = 13

14y = 13+8 (Adding 8 on both sides of equation)

14y = 21

y = 21/14 (Dividing both sides by 14)

y = 3/2 (Simplifying the equation)

**Question 11. Solve for p: 17 + 6p = 9**

**Solution:**

17 + 6p = 9

6p = 9 – 17 (Subtracting 17 from both sides of equation)

6p = -8

p = -8/6 (Dividing both sides by 6)

p = -4/3(Simplifying the equation)

**Question 12. Solve for x: x/3 + 1 = 7/15**

**Solution:**

x/3 + 1 = 7/15

x/3 = 7/15 – 1 (Subtracting both sides by 1)

x/3 = (7 – 15)/15 (Making common denominator)

x/3 = -8/15

x = -8/15 × 3 (Multiplying both sides by 3)

x = -8/5