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# Mechanical Bejeweled

like the computer game but no electricity
 (+5) [vote for, against]

i'm sure it could be done, you would just need mechanisms that could know when the three colors lined up, and then took the tiles from the bottom and filled them in randomly at the top.
 — JesusHChrist, Jan 14 2013

Tile matching games http://en.wikipedia...matching_video_game
[JesusHChrist, Jan 14 2013]

Candy Crush Saga is the most popular game on facebook http://venturebeat....QbHWxXkIoSCUUIWZ.02
do not try this game if you like money or time [JesusHChrist, Jan 18 2013]

I love bejewled. +
 — blissmiss, Jan 14 2013

Needs more detail
 — phundug, Jan 14 2013

[blissy] you forgot to press the croissant button!
 — xandram, Jan 14 2013

 I can not imagine how it would be done mechanically.

1) Detect whenever there are 3 in a row or 3 in two rows or whatever 2) Eject just those three
 — Kansan101, Jan 14 2013

Mechanical turk counts as "mechanical," right?

And the proposed mechanism is...?
 — Hive_Mind, Jan 15 2013

 I have no doubt this is mechanically feasible, by way of each jewel having a key mechanism in place, with the lock having x solutions where (x) is the number of types of jewels involved, and a solution is defined as three identical keys lining up.

 Once the mechanism unlocked, the board would be tilted and the jewels weighted such that they fall out by gravity.

 The swapping mechanism would have to be approximated, most likely by making it so that any jewel can be pulled out, but once one is gone, only adjacent jewels can be removed, and the drop mechanism would only trigger when all jewels were in place (triggering the drop mechanism may involve pulling a lever after each move).

 Positioning and loading the extra jewels would be difficult, so you would most likely use a long throw lever that also picked and oriented them as stages before feeding them to a drop in place mechanism at the top.

What might prove difficult would be over-length plays where four or five jewels in a row were triggered, as that adds a layer of mechanism complexity. Also a problem is that the jewel reserve would have to be significantly larger than the board size in order for the newly loaded jewels to approximate randomness.
 — MechE, Jan 15 2013

Sorry, I sick xandie. I push twice this time round.
 — blissmiss, Jan 15 2013

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