# Line slope calculator 3x+2y=40

**Straight line given by points A[8; 8] and B[10; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.5x+20

**Canonical form of the line equation:**3x+2y-40 = 0

**Parametric form of the line equation:**

x = 2t+8

y = -3t+8 ; t ∈ R

**Slope:**m = -1.5

**Slope angle of line: φ =**-56°18'36″ = -0.9828 rad

**X intercept:**x

_{0}= 13.3333

**Y intercept:**y

_{0}= q = 20

**Distance line from the origin:**d

_{0}= 11.094

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(2; -3)

**Normal vector: n =**(3; 2)

**Midpoint of the segment AB: M =**[9; 6.5]

**Perpendicular Bisector equation:**2x-3y+1.5 = 0

**Vector OA = (8; 8) ; |OA| = 11.3137**

**Vector OB = (10; 5) ; |OB| = 11.1803**

**Scalar product OA .OB = 120**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**