# Line slope calculator x-4y=-8

**Straight line given by points A[0; 2] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x+2

**Canonical form of the line equation:**x-4y+8 = 0

**Parametric form of the line equation:**

x = 4t

y = t+2 ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= -8

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9403

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[2; 2.5]

**Perpendicular Bisector equation:**4x+y-10.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**