# Line slope calculator 2x+5y=32

**Straight line given by points A[1; 6] and B[6; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+6.4

**Canonical form of the line equation:**2x+5y-32 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -2t+6 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 6.4

**Distance line from the origin:**d

_{0}= 5.9423

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[3.5; 5]

**Perpendicular Bisector equation:**5x-2y-7.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (6; 4) ; |OB| = 7.2111**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 46°50'51″ = 0.8176 rad**