# Line slope calculator x-5y=-8

**Straight line given by points A[2; 2] and B[7; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+1.6

**Canonical form of the line equation:**x-5y+8 = 0

**Parametric form of the line equation:**

x = 5t+2

y = t+2 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -8

**Y intercept:**y

_{0}= q = 1.6

**Distance line from the origin:**d

_{0}= 1.5689

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**5x+y-25 = 0

**Vector OA = (2; 2) ; |OA| = 2.8284**

**Vector OB = (7; 3) ; |OB| = 7.6158**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 21°48'5″ = 0.3805 rad**