# Line slope calculator x+6y=16

**Straight line given by points A[4; 2] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.1667x+2.6667

**Canonical form of the line equation:**x+6y-16 = 0

**Parametric form of the line equation:**

x = 6t+4

y = -t+2 ; t ∈ R

**Slope:**m = -0.1667

**Slope angle of line: φ =**-9°27'44″ = -0.1651 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 2.6667

**Distance line from the origin:**d

_{0}= 2.6304

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; -1)

**Normal vector: n =**(1; 6)

**Midpoint of the segment AB: M =**[7; 1.5]

**Perpendicular Bisector equation:**6x-y-40.5 = 0

**Vector OA = (4; 2) ; |OA| = 4.4721**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 20°51'16″ = 0.364 rad**