# Line slope calculator 5x+9y=90

**Straight line given by points A[0; 10] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.5556x+10

**Canonical form of the line equation:**5x+9y-90 = 0

**Parametric form of the line equation:**

x = 9t

y = -5t+10 ; t ∈ R

**Slope:**m = -0.5556

**Slope angle of line: φ =**-29°3'17″ = -0.5071 rad

**X intercept:**x

_{0}= 18

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 8.7416

**The length of the segment AB: |AB| =**10.2956

**Vector: AB =**(9; -5)

**Normal vector: n =**(5; 9)

**Midpoint of the segment AB: M =**[4.5; 7.5]

**Perpendicular Bisector equation:**9x-5y-3 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 60°56'43″ = 1.0637 rad**