Half a croissant, on a plate, with a sign in front of it saying '50c'
h a l f b a k e r y
I like this idea, only I think it should be run by the government.

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Binary Lottery

Zero/One sum game
  (+3)
(+3)
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against]

People bemoan the low probability of a lottery jackpot win - maybe if the odds were better, more people would participate.

So, taking this to the extreme (or the most mediocre, depending on your point of view) how about a lottery where each participant picks between a 1 and a 0.

At the end of the week, the choice that received the fewest votes is declared the winner, and the winnings are divvied up to the nearest penny and shared out amongst all winning players (subject to a small deduction regards fees, unclaimed prizes, rounding differences etc)

Zeuxis, Jan 06 2014

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       I like the strategic possibilities of playing this game.
pocmloc, Jan 06 2014
  

       All lotteries are binary. You either win or you don't.
MaxwellBuchanan, Jan 06 2014
  

       Rush to your nearest gas station or convenience store to buy a Binary Lottery ticket! A $1.00 ticket buys you a chance to win a life-changing $1.96!
swimswim, Jan 06 2014
  

       Reasonably presuming that the population (n) of ticket buyers is unbiased then you are playing double or nothing for n even, and the rather interesting 2n^2/(n^2-1) on average (which approaches 2 quite rapidly), or nothing for n odd. (all the above minus an admin fee of course). This is called double your money half of the time, and you may as well just not play. On the other hand...   

       Let's assume a unit value for a ticket. Let's assume there are n unbiased players, on average, where n is even. This doesn't require access to knowledge of current ticket sales, just prior history and averages. So no hacking and skulduggery. If I buy another n/2 tickets of only the one and another n/2 of only the zero. Then the total pot is a constant C times the pot n+n/2+n/2=2n. The constant C is slightly less than one to account for the small deductions alluded to in the idea.   

       The total winnings will be the available pot over the amount of winning tickets.i.e 2Cn/(n/2+n/2) (my half plus the unbiased half.) of which Cn would be due to me as owner of half the tickets. So the only thing I could lose is (1-C)n. Regardless of ones or zeroes. Sounds like good money laundry to me.   

       Please start you most esteemed proposition at your earliest contrivance. My Uncle, the former Deputy Assistant Minister of The Reserve Federal West Bank of Brazzaville has funds with which he wants to execute this matter.
4whom, Jan 06 2014
  

       I bought 0 this week. Everyone's buying 0. Have you bought your 0 yet?
pocmloc, Jan 06 2014
  
      
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